55x^2+48xy-7y^2=

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Solution for 55x^2+48xy-7y^2= equation:


Simplifying
55x2 + 48xy + -7y2 = 0

Reorder the terms:
48xy + 55x2 + -7y2 = 0

Solving
48xy + 55x2 + -7y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(55x + -7y)(x + y) = 0

Subproblem 1

Set the factor '(55x + -7y)' equal to zero and attempt to solve: Simplifying 55x + -7y = 0 Solving 55x + -7y = 0 Move all terms containing x to the left, all other terms to the right. Add '7y' to each side of the equation. 55x + -7y + 7y = 0 + 7y Combine like terms: -7y + 7y = 0 55x + 0 = 0 + 7y 55x = 0 + 7y Remove the zero: 55x = 7y Divide each side by '55'. x = 0.1272727273y Simplifying x = 0.1272727273y

Subproblem 2

Set the factor '(x + y)' equal to zero and attempt to solve: Simplifying x + y = 0 Solving x + y = 0 Move all terms containing x to the left, all other terms to the right. Add '-1y' to each side of the equation. x + y + -1y = 0 + -1y Combine like terms: y + -1y = 0 x + 0 = 0 + -1y x = 0 + -1y Remove the zero: x = -1y Simplifying x = -1y

Solution

x = {0.1272727273y, -1y}

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